OTOY Forums

So this is the forumula?
(width x height x 3) / (1024^2) = number of Mb in memory

The guy in the post had a texture size 8000x6000 with jpg. file beeing 7.49Mb big
=48.000.000 x 3=144.000.000 / (1024^2)= 137Mb when loaded in the scene?

Then why did another user said "So your textures take "less"; ~11 Mb"

I must be doing something wrong here

I have no idea what the "true" formula is. When I had a graphic card with a small amount of RAM I couldn't get the "true" calculations to work with Octane. So I made up my own which pretty much worked out fine.
My calculation ratio is 3.85 . So if I had a JPG image of 8000x8000 pixels, my simple calculation was 8x8x3.85= 246.4MB. So when I added the image, the Octane RAM counter should add 246.4MB to the scene. Not the "true" calculation but it's fairly close to the Octane RAM counter and that's what I needed so it didn't crash. Try it!

Seem ok for me.
.jpg are usulay 2000x2000 so to your calculation that would be 2x2x3,85=15,40Mb of RAM.
If I have 10 of these in my scene wich are usualy for big floors....around 200Mb of memory on textures.
What aboth polygon count?
How that taken into VRAM?
eg. 1 million polys= .... VRAM

How come i can't post in other threads? I'd like to know if i should get the standalone version or a plugin version (what are the benefits/drawbacks of a plugin).

picajol wrote:Seem ok for me.
.jpg are usulay 2000x2000 so to your calculation that would be 2x2x3,85=15,40Mb of RAM.
If I have 10 of these in my scene wich are usualy for big floors....around 200Mb of memory on textures.
What aboth polygon count?
How that taken into VRAM?
eg. 1 million polys= .... VRAM

"..to render 26 million triangles you need around 4GB of VRAM." Roeland .@OTOY

Thanx!